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Настройка требований к сложности пароля и периодической смене : Oracle

18.04.2024 13:45


20.11.2014 12:30
OlegON
 
Код:
@?/rdbms/admin/utlpwdmg
ALTER PROFILE DEFAULT LIMIT
PASSWORD_LIFE_TIME 90
PASSWORD_GRACE_TIME 14
PASSWORD_REUSE_TIME 365
PASSWORD_REUSE_MAX 365
FAILED_LOGIN_ATTEMPTS 10
PASSWORD_LOCK_TIME 1
PASSWORD_VERIFY_FUNCTION verify_function_11g;
Итого (требования мне перечисляли, можете ввести свои).
профиль DEFAULT (все юзеры по умолчанию)
срок жизни пароля - 90 дней
за две недели до устаревания - предупреждения
нельзя повторно использовать пароль ранее, чем 365 дней
блокировать при переборе в 10 попыток на день.
Обратите внимание, что в первой же строчке выставляются требования
Код:
ALTER PROFILE DEFAULT LIMIT
PASSWORD_LIFE_TIME 180
PASSWORD_GRACE_TIME 7
PASSWORD_REUSE_TIME UNLIMITED
PASSWORD_REUSE_MAX UNLIMITED
FAILED_LOGIN_ATTEMPTS 10
PASSWORD_LOCK_TIME 1
PASSWORD_VERIFY_FUNCTION verify_function_11g;
требования к паролю
Цитата:
По крайней мере восемь символов
Отличается от имени пользователя, инвертированного имени пользователя
Строка с по крайней мере одной буквой и по крайней мере одной цифрой
Отличается от предыдущего пароля по крайней мере тремя буквами
20.11.2014 18:04
OlegON
 
Надеюсь, меня простят за приведение самого пакета, поскольку в нем примеры этой функции...
Цитата:
Rem
Rem $Header: utlpwdmg.sql 02-aug-2006.08:18:05 asurpur Exp $
Rem
Rem utlpwdmg.sql
Rem
Rem Copyright (c) 2006, Oracle. All rights reserved.
Rem
Rem NAME
Rem utlpwdmg.sql - script for Default Password Resource Limits
Rem
Rem DESCRIPTION
Rem This is a script for enabling the password management features
Rem by setting the default password resource limits.
Rem
Rem NOTES
Rem This file contains a function for minimum checking of password
Rem complexity. This is more of a sample function that the customer
Rem can use to develop the function for actual complexity checks that the
Rem customer wants to make on the new password.
Rem
Rem MODIFIED (MM/DD/YY)
Rem asurpur 05/30/06 - fix - 5246666 beef up password complexity check
Rem nireland 08/31/00 - Improve check for username=password. #1390553
Rem nireland 06/28/00 - Fix null old password test. #1341892
Rem asurpur 04/17/97 - Fix for bug479763
Rem asurpur 12/12/96 - Changing the name of password_verify_function
Rem asurpur 05/30/96 - New script for default password management
Rem asurpur 05/30/96 - Created
Rem


-- This script sets the default password resource parameters
-- This script needs to be run to enable the password features.
-- However the default resource parameters can be changed based
-- on the need.
-- A default password complexity function is also provided.
-- This function makes the minimum complexity checks like
-- the minimum length of the password, password not same as the
-- username, etc. The user may enhance this function according to
-- the need.
-- This function must be created in SYS schema.
-- connect sys/<password> as sysdba before running the script

CREATE OR REPLACE FUNCTION verify_function_11G
(username varchar2,
password varchar2,
old_password varchar2)
RETURN boolean IS
n boolean;
m integer;
differ integer;
isdigit boolean;
ischar boolean;
ispunct boolean;
db_name varchar2(40);
digitarray varchar2(20);
punctarray varchar2(25);
chararray varchar2(52);
i_char varchar2(10);
simple_password varchar2(10);
reverse_user varchar2(32);

BEGIN
digitarray:= '0123456789';
chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';

-- Check for the minimum length of the password
IF length(password) < 8 THEN
raise_application_error(-20001, 'Password length less than 8');
END IF;


-- Check if the password is same as the username or username(1-100)
IF NLS_LOWER(password) = NLS_LOWER(username) THEN
raise_application_error(-20002, 'Password same as or similar to user');
END IF;
FOR i IN 1..100 LOOP
i_char := to_char(i);
if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN
raise_application_error(-20005, 'Password same as or similar to user name ');
END IF;
END LOOP;

-- Check if the password is same as the username reversed

FOR i in REVERSE 1..length(username) LOOP
reverse_user := reverse_user || substr(username, i, 1);
END LOOP;
IF NLS_LOWER(password) = NLS_LOWER(reverse_user) THEN
raise_application_error(-20003, 'Password same as username reversed');
END IF;

-- Check if the password is the same as server name and or servername(1-100)
select name into db_name from sys.v$database;
if NLS_LOWER(db_name) = NLS_LOWER(password) THEN
raise_application_error(-20004, 'Password same as or similar to server name');
END IF;
FOR i IN 1..100 LOOP
i_char := to_char(i);
if NLS_LOWER(db_name)|| i_char = NLS_LOWER(password) THEN
raise_application_error(-20005, 'Password same as or similar to server name ');
END IF;
END LOOP;

-- Check if the password is too simple. A dictionary of words may be
-- maintained and a check may be made so as not to allow the words
-- that are too simple for the password.
IF NLS_LOWER(password) IN ('welcome1', 'database1', 'account1', 'user1234', 'password1', 'oracle123', 'computer1', 'abcdefg1', 'change_on_install') THEN
raise_application_error(-20006, 'Password too simple');
END IF;

-- Check if the password is the same as oracle (1-100)
simple_password := 'oracle';
FOR i IN 1..100 LOOP
i_char := to_char(i);
if simple_password || i_char = NLS_LOWER(password) THEN
raise_application_error(-20007, 'Password too simple ');
END IF;
END LOOP;

-- Check if the password contains at least one letter, one digit
-- 1. Check for the digit
isdigit:=FALSE;
m := length(password);
FOR i IN 1..10 LOOP
FOR j IN 1..m LOOP
IF substr(password,j,1) = substr(digitarray,i,1) THEN
isdigit:=TRUE;
GOTO findchar;
END IF;
END LOOP;
END LOOP;

IF isdigit = FALSE THEN
raise_application_error(-20008, 'Password must contain at least one digit, one character');
END IF;
-- 2. Check for the character
<<findchar>>
ischar:=FALSE;
FOR i IN 1..length(chararray) LOOP
FOR j IN 1..m LOOP
IF substr(password,j,1) = substr(chararray,i,1) THEN
ischar:=TRUE;
GOTO endsearch;
END IF;
END LOOP;
END LOOP;
IF ischar = FALSE THEN
raise_application_error(-20009, 'Password must contain at least one \
digit, and one character');
END IF;


<<endsearch>>
-- Check if the password differs from the previous password by at least
-- 3 letters
IF old_password IS NOT NULL THEN
differ := length(old_password) - length(password);

differ := abs(differ);
IF differ < 3 THEN
IF length(password) < length(old_password) THEN
m := length(password);
ELSE
m := length(old_password);
END IF;

FOR i IN 1..m LOOP
IF substr(password,i,1) != substr(old_password,i,1) THEN
differ := differ + 1;
END IF;
END LOOP;

IF differ < 3 THEN
raise_application_error(-20011, 'Password should differ from the \
old password by at least 3 characters');
END IF;
END IF;
END IF;
-- Everything is fine; return TRUE ;
RETURN(TRUE);
END;
/

-- This script alters the default parameters for Password Management
-- This means that all the users on the system have Password Management
-- enabled and set to the following values unless another profile is
-- created with parameter values set to different value or UNLIMITED
-- is created and assigned to the user.

ALTER PROFILE DEFAULT LIMIT
PASSWORD_LIFE_TIME 180
PASSWORD_GRACE_TIME 7
PASSWORD_REUSE_TIME UNLIMITED
PASSWORD_REUSE_MAX UNLIMITED
FAILED_LOGIN_ATTEMPTS 10
PASSWORD_LOCK_TIME 1
PASSWORD_VERIFY_FUNCTION verify_function_11G;



-- Below is the older version of the script

-- This script sets the default password resource parameters
-- This script needs to be run to enable the password features.
-- However the default resource parameters can be changed based
-- on the need.
-- A default password complexity function is also provided.
-- This function makes the minimum complexity checks like
-- the minimum length of the password, password not same as the
-- username, etc. The user may enhance this function according to
-- the need.
-- This function must be created in SYS schema.
-- connect sys/<password> as sysdba before running the script

CREATE OR REPLACE FUNCTION verify_function
(username varchar2,
password varchar2,
old_password varchar2)
RETURN boolean IS
n boolean;
m integer;
differ integer;
isdigit boolean;
ischar boolean;
ispunct boolean;
digitarray varchar2(20);
punctarray varchar2(25);
chararray varchar2(52);

BEGIN
digitarray:= '0123456789';
chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
punctarray:='!"#$%&()``*+,-/:;<=>?_';

-- Check if the password is same as the username
IF NLS_LOWER(password) = NLS_LOWER(username) THEN
raise_application_error(-20001, 'Password same as or similar to user');
END IF;

-- Check for the minimum length of the password
IF length(password) < 4 THEN
raise_application_error(-20002, 'Password length less than 4');
END IF;

-- Check if the password is too simple. A dictionary of words may be
-- maintained and a check may be made so as not to allow the words
-- that are too simple for the password.
IF NLS_LOWER(password) IN ('welcome', 'database', 'account', 'user', 'password', 'oracle', 'computer', 'abcd') THEN
raise_application_error(-20002, 'Password too simple');
END IF;

-- Check if the password contains at least one letter, one digit and one
-- punctuation mark.
-- 1. Check for the digit
isdigit:=FALSE;
m := length(password);
FOR i IN 1..10 LOOP
FOR j IN 1..m LOOP
IF substr(password,j,1) = substr(digitarray,i,1) THEN
isdigit:=TRUE;
GOTO findchar;
END IF;
END LOOP;
END LOOP;
IF isdigit = FALSE THEN
raise_application_error(-20003, 'Password should contain at least one digit, one character and one punctuation');
END IF;
-- 2. Check for the character
<<findchar>>
ischar:=FALSE;
FOR i IN 1..length(chararray) LOOP
FOR j IN 1..m LOOP
IF substr(password,j,1) = substr(chararray,i,1) THEN
ischar:=TRUE;
GOTO findpunct;
END IF;
END LOOP;
END LOOP;
IF ischar = FALSE THEN
raise_application_error(-20003, 'Password should contain at least one \
digit, one character and one punctuation');
END IF;
-- 3. Check for the punctuation
<<findpunct>>
ispunct:=FALSE;
FOR i IN 1..length(punctarray) LOOP
FOR j IN 1..m LOOP
IF substr(password,j,1) = substr(punctarray,i,1) THEN
ispunct:=TRUE;
GOTO endsearch;
END IF;
END LOOP;
END LOOP;
IF ispunct = FALSE THEN
raise_application_error(-20003, 'Password should contain at least one \
digit, one character and one punctuation');
END IF;

<<endsearch>>
-- Check if the password differs from the previous password by at least
-- 3 letters
IF old_password IS NOT NULL THEN
differ := length(old_password) - length(password);

IF abs(differ) < 3 THEN
IF length(password) < length(old_password) THEN
m := length(password);
ELSE
m := length(old_password);
END IF;

differ := abs(differ);
FOR i IN 1..m LOOP
IF substr(password,i,1) != substr(old_password,i,1) THEN
differ := differ + 1;
END IF;
END LOOP;

IF differ < 3 THEN
raise_application_error(-20004, 'Password should differ by at \
least 3 characters');
END IF;
END IF;
END IF;
-- Everything is fine; return TRUE ;
RETURN(TRUE);
END;
/

-- This script alters the default parameters for Password Management
-- This means that all the users on the system have Password Management
-- enabled and set to the following values unless another profile is
-- created with parameter values set to different value or UNLIMITED
-- is created and assigned to the user.

-- Enable this if you want older version of the Password Profile parameters
-- ALTER PROFILE DEFAULT LIMIT
-- PASSWORD_LIFE_TIME 60
-- PASSWORD_GRACE_TIME 10
-- PASSWORD_REUSE_TIME 1800
-- PASSWORD_REUSE_MAX UNLIMITED
-- FAILED_LOGIN_ATTEMPTS 3
-- PASSWORD_LOCK_TIME 1/1440
-- PASSWORD_VERIFY_FUNCTION verify_function;
21.11.2014 12:28
bayan
 
Полезная штука, пользуюсь давно. Добавлю, что посмотреть текущие значения из sqlplus можно так:
Код:
select * from dba_profiles order by 1;
21.11.2014 12:33
OlegON
 
Я тут про ресурс-менеджер писал, если что, еще круче и более гибкий. Только вот клинило у меня его несколько раз на 10g
21.11.2014 12:58
bayan
 
Цитата:
OlegON Я тут про ресурс-менеджер писал, если что, еще круче и более гибкий. Только вот клинило у меня его несколько раз на 10g
Пока как то не попёр он у нас. И некогда и под задачи не особо подходит. Авторизация у нас на уровне приложения, к сожалению.
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